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Postings from June 2015
On Mon, 22 Jun 2015 17:58:46 -0700, Jan Dubois <jand@activestate.com> wrote: > > shift by too many bits == shift by n modulo wordbits? > > (with a sane definition of modulo for negative -n...) > > Surely a right shift by too many bits should result in 0. > I'm less sure about the left shift, but I think I would rather see the > far left bits dropped. >> → 0 << → NaN ? -- H.Merijn Brand http://tux.nl Perl Monger http://amsterdam.pm.org/ using perl5.00307 .. 5.21 porting perl5 on HP-UX, AIX, and openSUSE http://mirrors.develooper.com/hpux/ http://www.test-smoke.org/ http://qa.perl.org http://www.goldmark.org/jeff/stupid-disclaimers/Thread Previous | Thread Next