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Postings from June 2015
Ricardo Signes wrote:
>I think they're being treated in the same way, insofar as that way is "leave it
>mostly be."
No, shifting right by a whole lot currently does not yield zero.
Its undefined behaviour tends to be modulo-word-size in the same
situations as that for left shifts.
$ perl -lwe 'print ~0 >> 500'
>I think exposing the underlying representation would be a bit much.
We already expose the word size in defined shifting behaviour.
$ perl -lwe '$a=1;$t=0;while($a){$a<<=1;$t++;} print "word size $t"'
>"use integer" is meant to do that.
For shifts it doesn't really make a difference there, because shifting
is already an integer-specific operation. "use integer" only affects
whether we treat the integer word as signed.
-zefram
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